用laravel 框架想实现一个分页接口，返回数据表中其中一部分字段
$list = DB::table('booklist_table')->orderBy('create_time','asc')->paginate($size,['id','title','author','image'])->toJson();
return json_decode($list,true);
结果运行报错
"SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' `title`, `author`, `image`) as aggregate from `booklist_table`' at line 1 (SQL: select count(`id`, `title`, `author`, `image`) as aggregate from `booklist_table`) ◀"
后来经过查询原因将代码改为
$list = DB::table('booklist_table')->select('id','title','author','image')->orderBy('create_time','asc')->paginate($size)->toJson();
结果正确！
以上这篇laravel 解决paginate查询多个字段报错的问题就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持脚本之家。
您可能感兴趣的文章:- laravel 执行迁移回滚示例
- Laravel 5框架学习之数据库迁移(Migrations)
- Laravel5.5 数据库迁移:创建表与修改表示例
- laravel解决迁移文件一次删除创建字段报错的问题
