pygame实现井字棋之第一步绘制九宫格

import pygame
import sys
# 初始化模块，加一下稳一些
pygame.init()
# 创建屏幕对象
screen = pygame.display.set_mode((width,height))
# 界面背景颜色渲染，放在while中会不断覆盖格子
screen.fill((255,255,255))
# 界面的标题
pygame.display.set_caption('井字棋')

# 刷新界面函数
def update():
    pass

# 游戏状态，0表示未分胜负，-1表示个人胜利，1表示电脑获胜
judge = 0

while not judge:
    update()
    # 感应事件
    for event in pygame.event.get():
    	# 点击关闭窗口，退出游戏
    	if event.type == pygame.QUIT:
            sys.exit()
    # 将渲染的界面显示
    pygame.display.flip()

# width、height已经给出
# 长/宽的三分之一，为一个格子的长宽
single = width/3
# 表示九个格子
rect = [0]*9
rect[0] = pygame.draw.rect(screen,(255,228,181),((0,0),(single,single)),width=1)
rect[1] = pygame.draw.rect(screen,(255,228,181),((single,0),(single,single)),width=1)
rect[2] = pygame.draw.rect(screen,(255,228,181),((single*2,0),(single,single)),width=1)
rect[3] = pygame.draw.rect(screen,(255,228,181),((0,single),(single,single)),width=1)
rect[4] = pygame.draw.rect(screen,(255,228,181),((single,single),(single,single)),width=1)
rect[5] = pygame.draw.rect(screen,(255,228,181),((single*2,single),(single,single)),width=1)
rect[6] = pygame.draw.rect(screen,(255,228,181),((0,single*2),(single,00)),width=1)
rect[7] = pygame.draw.rect(screen,(255,228,181),((single,single*2),(single,single)),width=1)
rect[8] = pygame.draw.rect(screen,(255,228,181),((single*2,800),(single,single)),width=1)

# lattice.py
class Lattice():
    def __init__(self,rect):
        self.rect = rect
        # 0表示初始，1表示个人-1表示电脑
        self.stats = 0
	
	# 渲染矩阵
    def draw(self):
        # 按照状态显示
        if self.stats == -1:
            pass
        elif self.stats == 0:
            pass
        else:
            pass

from lattice import Lattice

for i in range(len(rect)):
    rect[i] = Lattice(rect[i])