Ruby中用线程实现经典的生产者消费者问题代码实例

require "thread"
puts "ProAndCon"
  
queue = Queue.new    #用队列Queue实现线程同步 
  
producer = Thread.new do
    10.times do |i| 
        sleep rand(i) # 让线程睡眠一段时间 
        queue i 
        puts "#{i} produced"
    end
end
  
consumer = Thread.new do
    10.times do |i| 
        value = queue.pop 
        sleep rand(i/2) 
        puts "consumed #{value}"
    end
end
  
consumer.join  #等待consumer线程的输出完成再关闭此进程

ProAndCon
produced
produced
consumed 0
produced
produced
consumed 1
consumed 2
consumed 3
produced
consumed 4
produced
consumed 5